39s^2-8s=0

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Solution for 39s^2-8s=0 equation:



39s^2-8s=0
a = 39; b = -8; c = 0;
Δ = b2-4ac
Δ = -82-4·39·0
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8)-8}{2*39}=\frac{0}{78} =0 $
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8)+8}{2*39}=\frac{16}{78} =8/39 $

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